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Vba implements example
Vba implements example






vba implements example

I have created a recorded macro that will take each cell from the 1st row and place it in the proper place on the “report spreadsheet” and then print the spreadsheet. I will need to do this for each row of data – thus, I will need to do this 100x. I am able to do this with my current level of knowledge. This spreadsheet is designed to look like a report.

vba implements example

I would like to take data from each row – one row at a time and copy into another spreadsheet. I have a spreadsheet that contains 100 rows. Do you have a code for the following scenario? Unfortunately, it does not cover what I am trying to do. Characters(J, Len(myStr)).Font.ColorIndex = 3 MyStr = myRg.Range(“B1”).Offset(I, 0).Value MsgBox “the selected range can only contain two columns ” (“please select the data range:”, “Selection Required”, myTxt,, ,, , 8) I am not able to run this code it giving me an error of “Variable required. MsgBox "Your Pivot Table is now updated." Pivot_Sheet.PivotTables(PivotName).RefreshTable PivotCaches.Create(SourceType:=xlDatabase, SourceData:=NewRange) 'Change Pivot Table Data Source Range Address NewRange = Data_Sheet.Name & "!" & DataRange.Address(ReferenceStyle:=xlR1C1)

vba implements example

Set DataRange = Data_Sheet.Range(StartPoint, Cells(DownCell, LastCol)) LastCol = StartPoint.End(xlToRight).Column Set Pivot_Sheet = ThisWorkbook.Worksheets("Pivot3") Set Data_Sheet = ThisWorkbook.Worksheets("PivotTableData3")








Vba implements example